c^2-13c+42=0

Solution for c^2-13c+42=0 equation:

Simplifying
c2 + -13c + 42 = 0

Reorder the terms:
42 + -13c + c2 = 0

Solving
42 + -13c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(6 + -1c)(7 + -1c) = 0

Subproblem 1
Set the factor '(6 + -1c)' equal to zero and attempt to solve:

Simplifying
6 + -1c = 0

Solving
6 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1c = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1c = 0 + -6
-1c = 0 + -6

Combine like terms: 0 + -6 = -6
-1c = -6

Divide each side by '-1'.
c = 6

Simplifying
c = 6
Subproblem 2
Set the factor '(7 + -1c)' equal to zero and attempt to solve:

Simplifying
7 + -1c = 0

Solving
7 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1c = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1c = 0 + -7
-1c = 0 + -7

Combine like terms: 0 + -7 = -7
-1c = -7

Divide each side by '-1'.
c = 7

Simplifying
c = 7
Solution
c = {6, 7}